## What is Alligation method in maths?

Alligation is an old and practical method of solving arithmetic problems related to mixtures of ingredients. Alligation medial is merely a matter of finding a weighted mean. Alligation alternate is more complicated and involves organizing the ingredients into high and low pairs which are then traded off.

## How do you solve an Alligation problem?

By the alligation Rule, milk and water are in the ratio of 5: 1. quantity of milk in the mixture = 5 ×16 = 80 litres. Ex3: 300 gm of sugar solution has 40% sugar in it. How much sugar should be added to make it 50% of the solution?

## What is the ratio of water mixed with milk to gain 16 2 3?

Mixture and Alligation #19

19. In what ratio must water be mixed with milk to gain 1623% 16 2 3 % on selling the mixture at cost price? | |
---|---|

A. 1 : 4 | B. 6 : 1 |

C. 1 : 6 | D. 4 : 1 |

## How do you solve mixture ratio problems?

Solution using conceptual reasoning: Milk in the beginning is seven eighth of 40 liters, that is, 35 liters and rest 5 liters was water. Milk amount is not changed and by the desired ratio it has to be 3 times the water in the new mixture. This volume of water in the new mixture is then, liters.

## How many gallons of 15% sugar solution must be mixed with 5 gallons of a 40% sugar solution to make a 30% solution?

Your answer, in that case, is that gallons of a 15% solution plus 5 gallons of a 40% solution are required to make 15 gallons of a 30% solution. 2.5 + 2 = 4.5 gallons of solution from the 15% and 40% solution. .

## What quantity of a 60% acid solution must be mixed with a 30% solution to produce 300 ml of a 50% solution?

SOLUTION: What quantity of a 60% acid solution must be mixed with a 30% solution to produce 300mL of a 50% solution? x=200 ml of 60% is used. 300-200=100 ml of 30% is used.

## What quantity of a 70% acid solution must be mixed with a 40% solution to produce 600 mL of a 60% solution?

SOLUTION: what quantity of a 70% acid solution must be mixed with a 40% solution to produce 600mL of a 60% solution? Question 350378: what quantity of a 70% acid solution must be mixed with a 40% solution to produce 600mL of a 60% solution? X=400 ml. of 70% solution is used.

## How many liters of a 20% alcohol solution must be mixed with 60 liters of a 90% solution to get a 30% solution?

x=liters of 20% alcohol solution to be mixed with 60 liters of 90% alcohol solution. ans: 80 liters of a 20% alcohol solution must be mixed with 60 L of a 90% alcohol solution to get a 50% alcohol solution.

## What amount of pure acid must be added to 300 mL of a 50 acid solution to produce a 60 acid solution?

SOLUTION: what quantity of pure acid must be added to 300mL of a 50% acid solution to produce a 60% acid solution? Question 1123843: what quantity of pure acid must be added to 300mL of a 50% acid solution to produce a 60% acid solution? = 75 mL.

## How many grams of pure acid must be added to 40 grams of a 20% acid solution to make a solution which is 36% acid?

SOLUTION: How many grams of pure acid must be added to 40 grams of a 20% acid solution to make a solution that is 36% acid? Question 1068232: How many grams of pure acid must be added to 40 grams of a 20% acid solution to make a solution that is 36% acid? x=grams of pure acid. x=10 gms.

## How much pure acid must be added to 50ml of a 35% acid solution to produce a mixture that is 75% acid?

How much pure acid must be added to 50 mL of a 35% acid solution to produce a mixture that is 75% acid? (See Figure 2.58.) FIGURE 2.58 Mixing solutions. We need to add 80 mL of pure acid to the 35% acid solution to make a solution that is 75% acid. Now try Exercise 31.

## How many liters is a 20% solution?

500 = 20x + 400 Subtract 400 from both sides. 100 = 20x Divide both sides by 20. Therefore, 5 liters of a 20% solution must be added to 10 liters of a 50% solution to make a 40% solution.

## How many liters l of a 20% alcohol solution must be mixed with 60 l of a 90% solution to get a 80% solution?

Each L of the 20% solution contributes 0.2 L of alcohol and thus a total of 0.2x L of alcohol, while the 60 L of 90% solution contributes 54 L of alcohol. Solve for x: So you will need 30 L of the 20% solution.

## How many liters of a 30% alcohol solution should be added to 40 liters of a 60% alcohol solution to prepare a 50% solution?

75. How many litres of a 30% alcohol solution should be added to 40 litres of a 60% alcohol solution to prepare a 50% solution? \ The ratio in which 30% alcohol and 60% alcohol should be mixed to get 50% alcohol is 1 : 2.

## How many liters of a solution that is 30% alcohol must be mixed with 80 liters of a solution that is 90% alcohol to get a solution that is 60% alcohol?

That means you need 45 liters of the 30% solution.

## How many liters of distilled water must be added to 80 liters of a 60 acid solution to obtain a 50% acid solution?

Answer: how many liters of distilled water must be added to 80 liters of 60% acid solution to obtain a 50 % acid solution? (80*0.60)=48 L of 100% acid. To make 50% acid, it must be diluted to have a total volume of 48/(0.5)=96 L.

## How much of a 10% alcohol solution must be mixed with 20 gallons of a 15% alcohol solution to obtain a solution that is exactly 13% alcohol?

Question: How Much Of A 10% Alcohol Solution Must Be Mixed With 20 Gallons Of A 15% Alcohol Solution To Obtain A Solution That Is Exactly 13% Alcohol? 13 Gallons.

## How many liters of a 70 alcohol solution must be added to 50 liters of a 40 alcohol solution?

TAGS. How many liters of a 70% alcohol solution must be added to 50 liters of a 40% alcohol solution to produce a 50% alcohol solution? Hence Sol 1 will be 25.

## How much alcohol must be added to 24 gallons of a 14% solution of alcohol in order to produce a 20% solution?

2 * x = 4.8 – 3.36. simplify to get . 8 * x = 1.44. this says that you need to add 1.8 gallons of pure alcohol to get a solution that is 20% alcohol.

## How much water should we add to 5 gallons of 18% acid solution to dilute it to a concentration of 10 %?

4 gallons of water is needed to dilute to a concentration of 10%. Step-by-step explanation: It is given that, The 5 gallons of water contains 18% of acid solution.

## How many gallons of a 5% acid solution must be mixed with 5 gal of a 10% solution to obtain a 7% solution?

You will need to add 7.5 gallons of 5% acid solution to 5 gallons of 10% acid solution to obtain 12.5 gallons of 7% acid solution.

## How many liters of a 15% acid solution should be mixed with 10 liters of a 36% acid solution to obtain a mixture that is 20%?

32 liters

## How much pure acid should be mixed with 2 gallons of a 40 acid solution to get a 70 acid solution?

SOLUTION: how much pure acid should be mixed with 2 gallons of a 40% acid solution in order to get a 70% acid solution. x + 2(0.4) = (2+x)(0.7) Simplify and solve for x. x+0.8 = 1.4+0.7x Subtract 0.7x from both sides. 0.3x+0.8 = 1.4 Now subtract 0.8 from both sides.

## How much pure acid should be mixed with 5 gallons of a 50 acid solution?

1 Expert Answer You need 7.5 cgallons of pure acid.

## How much pure acid should be mixed with 2 gallons of a 70 acid solution to get a 90 acid solution?

of pure acid. You need add ‘x’ gallons of 100% pure acid to make a 90% solution. Answer: Add 2 gallons of pure acid to 2 gallons of 80% acid to make a 90% acid solution.